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将大智慧的MACD顶底背离改成通达信

指标答疑4年前 (2022-11-25)44
将大智慧的MACD顶底背离改成通达信 编写要求:DIFF:EMA(CLOSE,7) - EMA(CLOSE,19);DEA:EMA(DIFF,9);MACD:2*(DIFF-DEA),COLORSTICK;A1:=BARSLAST(REF(CROSS(DIFF,DEA),1));B1:=REF(C,A1+1)˃C AND REF(DIFF,A1+1)C AN...
将大智慧的MACD顶底背离改成通达信

编写要求:

DIFF:EMA(CLOSE,7) - EMA(CLOSE,19);DEA:EMA(DIFF,9);MACD:2*(DIFF-DEA),COLORSTICK;A1:=BARSLAST(REF(CROSS(DIFF,DEA),1));B1:=REF(C,A1+1)>C AND REF(DIFF,A1+1)C AND REF("KDJ.K"(9,3,3),A2+1)<"KDJ.K"(9,3,3) AND CROSS("KDJ.K"(9,3,3),"KDJ.D"(9,3,3));A3:=BARSLAST(REF(CROSS("RSI.RSI1"(6,12,24),"RSI.RSI2"(6,12,24)),1));B3:=REF(C,A3+1)>C AND REF("RSI.RSI1"(6,12,24),A3+1)<"RSI.RSI1"(6,12,24) AND CROSS("RSI.RSI1"(6,12,24),"RSI.RSI2"(6,12,24));C1:=BARSLAST(REF(CROSS(DEA,DIFF),1));D1:=REF(C,C1+1)DIFF AND CROSS(DEA,DIFF);C2:=BARSLAST(REF(CROSS("KDJ.D"(9,3,3),"KDJ.K"(9,3,3)),1));D2:=REF(C,C2+1)"KDJ.K"(9,3,3) AND CROSS("KDJ.D"(9,3,3),"KDJ.K"(9,3,3));C3:=BARSLAST(REF(CROSS("RSI.RSI2"(6,12,24),"RSI.RSI1"(6,12,24)),1));D3:=REF(C,C3+1)"RSI.RSI1"(6,12,24) AND CROSS("RSI.RSI2"(6,12,24),"RSI.RSI1"(6,12,24));MACD底背:IF(B1>0,-0.1,0),COLORRED,POINTDOT;KDJ底背:IF(B2>0,-0.1,0),COLORFF00FF,POINTDOT;RSI底背:IF(B3>0,-0.1,0),COLORYELLOW,POINTDOT;MACD顶背:IF(D1>0,0.1,0),COLOR00FF00,POINTDOT;KDJ顶背:IF(D2>0,0.1,0),COLORFFCC66,POINTDOT;RSI顶背:IF(D3>0,0.1,0),COLORWHITE,POINTDOT;STICKLINE(B1>0,-0.2,0,4,0),COLORRED;STICKLINE(B2>0,-0.2,0,4,0),COLORFF00FF;STICKLINE(B3>0,-0.2,0,4,0),COLORYELLOW;STICKLINE(D1>0,0.2,0,4,0),COLOR00FF00;STICKLINE(D2>0,0.2,0,4,0),COLORFFCC66;STICKLINE(D3>0,0.2,0,4,0),COLORWHITE;STICKLINE(MACD>REF(MACD,1) AND MACD>0,0,MACD,0,0),COLORRED;STICKLINE(MACD<=REF(MACD,1) AND MACD>0,0,MACD,0,0),COLORYELLOW;STICKLINE(MACD=REF(MACD,1) AND MACD<0,0,MACD,0,0),COLORMAGENTA;STICKLINE(C>0,0,0,50,1),COLORBLUE;DIFF,COLORGREEN;DEA,COLORYELLOW;PARTLINE(DIFF,DIFF>MA(DIFF,2),RGB(255,0,0),DIFFMA(DEA,2),RGB(255,0,0),DEALOW+0.01,1,-0);

解答:

DIFF:EMA(CLOSE,7) - EMA(CLOSE,19);

DEA:EMA(DIFF,9);

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